Calculate to three significant digits the density of carbon monoxide gas at exactly -15 °C and exactly 1 atm. You can assume

Answer

Density of CO at −15 °C and 1 atm

🧪 Density of Carbon Monoxide (CO) Gas

Problem:

Calculate the density of CO gas under the following conditions:

  • Temperature: −15 °C
  • Pressure: 1.00 atm
  • Assume: Ideal gas behavior

Step 1: Convert Temperature to Kelvin

T = −15.0 + 273.15 = 258.15 K

Step 2: Ideal Gas Law in Terms of Density

PV = nRT
n = m / M, ρ = m / V → ρ = PM / RT

Step 3: Insert Known Values

  • P = 1.00 atm
  • M = 28.01 g/mol
  • R = 0.08206 L·atm/mol·K
  • T = 258.15 K

Step 4: Calculate

ρ = (1.00 × 28.01) / (0.08206 × 258.15)
ρ ≈ 28.01 / 21.1814 ≈ 1.322 g/L

✅ Final Answer:

ρ ≈ 1.32 g/L (rounded to three significant digits)

Summary:

  • Gas density increases with molar mass and pressure.
  • Gas density decreases with temperature.
  • This calculation assumes ideal gas behavior and uses the derived formula ρ = PM / RT.

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