You have an aqueous solution of sulfuric acid (H2SO4) at a concentration of 0.5molL. You then add sodium hydroxide (NaO

Answer

Question 4 – Sulfuric Acid Speciation at pH 7

Analysis of Sulfuric Acid Species at pH 7

Chemical Background

  • Sulfuric acid (H2SO4) is a strong diprotic acid.
  • It dissociates in two steps:
    1. H2SO4 → H+ + HSO4   (strong acid, pKa1 = -6.38)
    2. HSO4 ⇌ H+ + SO42−   (weak acid, pKa2 = 2.00)
  • At pH 7, both acidic protons have been neutralized by NaOH.

Species Present Above 0.1 mol/L

  • [SO42−] — Final form after complete deprotonation of H2SO4. Likely to be > 0.1 M.
  • [Na+] — Added via NaOH. Matches amount of OH added to neutralize both protons; present > 0.1 M.

Species Present Below 0.1 mol/L

  • [H2SO4] — Fully deprotonated at pH 7. Negligible concentration.
  • [HSO4] — pKa = 2. At pH 7, mostly converted to SO42−.
  • [H3O+] — [H+] = 10-7 M at pH 7, much less than 0.1 M.
  • [OH] — [OH] = 10-7 M at pH 7, also negligible.

Conclusion

At pH 7, the major species present above 0.1 mol/L are:

  • SO42− (fully deprotonated sulfuric acid)
  • Na+ (from NaOH neutralization)

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