
Answer
Organic Synthesis of Compounds i, ii, and iii
Provided Starting Materials:
- Benzyl bromide (C6H5CH2Br)
- Acetylene (HC≡CH)
- Cyclohexylmethyl bromide (BrCH2-Cyclohexane)
- 1,3-Dibromopropane (BrCH2CH2CH2Br)
🔹 Compound i: Tri-substituted Ether
Strategy: Synthesize via multistep Williamson ether synthesis using the alkoxides of benzyl alcohol and cyclohexylmethanol.
- Convert benzyl bromide to benzyl alcohol via SN2 with NaOH. Then deprotonate with NaH → benzyl alkoxide.
- React with 1 equivalent of 1,3-dibromopropane → intermediate mono-ether (with remaining Br).
- Convert cyclohexylmethyl bromide to cyclohexylmethanol → deprotonate to form alkoxide.
- React second alkoxide with mono-substituted intermediate → final tri-substituted ether.
🔹 Compound ii: Ethyl Benzoate (Ester)
Strategy: Oxidize benzyl bromide to benzoic acid and perform Fischer esterification with ethanol.
- Oxidize benzyl bromide with KMnO4 → benzoic acid.
- React benzoic acid with ethanol in H+/heat → ethyl benzoate.
- Ethanol can be assumed available or derived from reduction/cleavage of suitable diol intermediates.
🔹 Compound iii: Epoxide with Phenethyl and Butyl Side Chains
Strategy: Build a substituted alkene, then oxidize it to the epoxide.
- React benzyl bromide with deprotonated acetylene (NaNH2) → phenyl-propyne.
- Partial hydrogenation (Lindlar’s catalyst) → cis-alkene.
- Alkylate with 1-bromobutane or equivalent → 1-phenyl-1-butene.
- Epoxidize using mCPBA or peracid → substituted epoxide (as shown).
🧾 Summary Table:
| Compound | Key Reaction | Key Reagents | Intermediates |
|---|---|---|---|
| i (Ether) | Williamson ether synthesis | NaH, alkoxides, 1,3-dibromopropane | Benzyl alkoxide, mono-substituted ether |
| ii (Ester) | Fischer esterification | KMnO4, H+, EtOH | Benzoic acid |
| iii (Epoxide) | Epoxidation of alkene | NaNH2, Lindlar, mCPBA | Phenylalkyne, alkene |
