Name compound C.Write its molecular formula.Calculate its molecular weight. Use C=12, H=1, O=16.Write a series of steps to make compound C, via

Analysis and Synthesis of Compound C
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Name of Compound C:
The structure represents a carboxylic acid with a methyl group at the α-carbon. It is named 2-methylbutanoic acid. -
Molecular Formula:
Counting all atoms: C5, H10, O2
C5H10O2 -
Molecular Weight:
– Carbon (C): 5 × 12 = 60
– Hydrogen (H): 10 × 1 = 10
– Oxygen (O): 2 × 16 = 32
Total: 60 + 10 + 32 = 102 g/mol -
Synthesis of Compound C from the given alkene (2-methyl-1-butene):
The target is a carboxylic acid via a nitrile intermediate:-
Step 1 – Hydroboration-Oxidation: Convert the terminal alkene to a primary alcohol.
Reagents:1) BH3, THF 2) H2O2, OH⁻ -
Step 2 – Oxidation of Alcohol to Alkyl Bromide:
Reagents:PBr3to form the alkyl bromide (SN2 suitable). -
Step 3 – Nitrile Formation: Substitute Br with CN.
Reagents:NaCNin acetone → forms the nitrile. -
Step 4 – Hydrolysis of the Nitrile to Carboxylic Acid:
Reagents:H3O⁺, heatorNaOH, heat then HCl
Final product: 2-methylbutanoic acid.
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Step 1 – Hydroboration-Oxidation: Convert the terminal alkene to a primary alcohol.
