The landing speed of an airplane is 7 m/s faster than its stalling speed. What is the relationship between the two speeds, and how can this be expressed?

Landing Speed and Stalling Speed Relationship in Airplanes

Physics of Flight: Landing Speed vs. Stalling Speed

Question:

The landing speed of an airplane is 7 m/s faster than its stalling speed. What is the relationship between the two speeds, and how can this be expressed?

Answer:

Let us define the variables first to understand the relationship:

  • vs = Stalling speed of the airplane (in m/s)
  • v = Landing speed of the airplane (in m/s)

Step 1: Understand the given relationship

According to the problem, the airplane’s landing speed is 7 m/s faster than its stalling speed.

v = vs + 7

This equation shows a simple linear relationship between landing and stalling speeds. Regardless of the specific value of vs, the landing speed will always be 7 m/s higher.

Step 2: Example Calculation

If the airplane has a stalling speed of:

vs = 60 m/s

Then the landing speed will be:

v = 60 + 7 = 67 m/s

Conclusion:

The landing speed of an aircraft must be higher than its stalling speed to ensure stability and control during the final approach. The margin (in this case, 7 m/s) helps prevent stall conditions while landing.

Thus, the relationship is accurately expressed as:

v = vs + 7

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