If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm?
Answer
🌡️ Gas Law Calculation – Volume Change with Pressure
🔍 Step 1: Identify the Given Information
- Initial Volume (V₁) = 2.8 L
- Initial Pressure (P₁) = 1.8 atm
- Final Pressure (P₂) = 1.2 atm
- Final Volume (V₂) = ?
⚖️ Step 2: Apply Boyle’s Law
Since temperature and amount of gas remain constant, we use Boyle’s Law:
P₁ × V₁ = P₂ × V₂
✏️ Step 3: Rearrange to Solve for V₂
V₂ = (P₁ × V₁) / P₂
= (1.8 atm × 2.8 L) / 1.2 atm
= 5.04 / 1.2 = 4.2 L
= (1.8 atm × 2.8 L) / 1.2 atm
= 5.04 / 1.2 = 4.2 L
✅ Final Answer:
The volume of the gas will be 4.2 liters at 1.2 atm pressure.
💡 Tip: According to Boyle’s Law, pressure and volume are inversely related—when pressure decreases, volume increases, provided temperature and number of moles remain constant.