
Answer
Atom Count Comparison
To determine the number of atoms in each compound, we first calculate the number of moles using the formula:
Moles = Given Mass ÷ Molar Mass
Moles Present:
Na₂CO₃: 212 ÷ 106 = 2 mol
Na₂O: 248 ÷ 62 = 4 mol
NaOH: 240 ÷ 40 = 6 mol
H₂: 12 ÷ 2 = 6 mol
CO₂: 220 ÷ 44 = 5 mol
Na₂O: 248 ÷ 62 = 4 mol
NaOH: 240 ÷ 40 = 6 mol
H₂: 12 ÷ 2 = 6 mol
CO₂: 220 ÷ 44 = 5 mol
Total Atoms = moles × NA × atomicity
Na₂CO₃ → 2 mol × 6 = 12 NA
Na₂O → 4 mol × 3 = 12 NA
H₂ → 6 mol × 2 = 12 NA
NaOH → 6 mol × 3 = 18 NA
CO₂ → 5 mol × 3 = 15 NA
Na₂O → 4 mol × 3 = 12 NA
H₂ → 6 mol × 2 = 12 NA
NaOH → 6 mol × 3 = 18 NA
CO₂ → 5 mol × 3 = 15 NA
Thus, A (Na₂CO₃), B (Na₂O), and D (H₂) contain equal numbers of atoms: 12 NA each.
