Among the following, choose the ones with equalnumber of atoms.A. 212 g of Na2CO3 (s) [molar mass = 106 g]B. 248 g of Na2O (s) [molar mass = 62 g]C. 240 g of NaOH (s) [molar mass = 40 g]D. 12 g of H2(g) [molar mass = 2 g]E. 220 g of CO2(g) [molar mass = 44 g]Choose the correct answer from the options givenbelow:

Answer

Atom Count Comparison

Atom Count Comparison

To determine the number of atoms in each compound, we first calculate the number of moles using the formula:

Moles = Given Mass ÷ Molar Mass

Moles Present:

Na₂CO₃: 212 ÷ 106 = 2 mol
Na₂O: 248 ÷ 62 = 4 mol
NaOH: 240 ÷ 40 = 6 mol
H₂: 12 ÷ 2 = 6 mol
CO₂: 220 ÷ 44 = 5 mol

Total Atoms = moles × NA × atomicity

Na₂CO₃ → 2 mol × 6 = 12 NA
Na₂O → 4 mol × 3 = 12 NA
H₂ → 6 mol × 2 = 12 NA
NaOH → 6 mol × 3 = 18 NA
CO₂ → 5 mol × 3 = 15 NA
Thus, A (Na₂CO₃), B (Na₂O), and D (H₂) contain equal numbers of atoms: 12 NA each.

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