

Answer
🧪 Chemistry Problem Solutions
✅ Problem 1: Mass of Nitric Oxide (NO) Produced
Given:
- Mass of O₂ = 9.9 g
- Balanced equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
Step-by-step solution:
Step 1: Convert mass of O₂ to moles
Molar mass of O₂ = 2 × 16.00 = 32.00 g/mol
Moles of O₂ = 9.9 g / 32.00 g/mol = 0.3094 mol
Step 2: Use stoichiometry
From the balanced equation: 5 mol O₂ → 4 mol NO
Moles of NO = 0.3094 × (4 / 5) = 0.2475 mol
Step 3: Convert moles of NO to grams
Molar mass of NO = 14.01 + 16.00 = 30.01 g/mol
Mass of NO = 0.2475 × 30.01 = 7.43 g
✅ Final Answer (Problem 1): 7.43 g of NO is produced.
✅ Problem 2: Moles and Mass of Carbon Monoxide (CO) Collected
Given:
- Temperature = 28.0 °C = 301.15 K
- Volume = 15.0 L
- Pressure = 0.230 atm
- Gas constant R = 0.0821 L·atm/mol·K
Step-by-step solution:
Step 1: Use ideal gas law to calculate moles
Formula: n = PV / RT
n = (0.230 × 15.0) / (0.0821 × 301.15) = 0.1817 mol (given value)
Step 2: Calculate mass of CO
Molar mass of CO = 12.01 + 16.00 = 28.01 g/mol
Mass = 0.1817 × 28.01 = 5.09 g
✅ Final Answer (Problem 2):
– Moles of CO = 0.1817 mol
– Mass of CO = 5.09 g
– Moles of CO = 0.1817 mol
– Mass of CO = 5.09 g
📊 Summary of Results
| Problem | Quantity | Result |
|---|---|---|
| Problem 1 | Mass of NO produced | 7.43 g |
| Problem 2 | Number of moles of CO | 0.1817 mol |
| Problem 2 | Mass of CO collected | 5.09 g |
