Answer
🧪 Theoretical Mass of Anhydrous Magnesium Sulfate and Water
🔬 Objective
Calculate the theoretical mass of:
- Anhydrous magnesium sulfate (MgSO₄)
- Water vapor (H₂O)
Given: 8.325 g of magnesium sulfate heptahydrate (MgSO₄·7H₂O)
⚛️ Balanced Chemical Equation
MgSO₄·7H₂O (s) → MgSO₄ (s) + 7 H₂O (g)
From 1 mol of hydrate, we get:
- 1 mol of MgSO₄
- 7 mol of H₂O
Step 1: Moles of MgSO₄·7H₂O
Molar mass of MgSO₄·7H₂O = 246.472 g/mol
Moles = 8.325 g / 246.472 g/mol = 0.0338 mol
Step 2: Mass of MgSO₄
Molar mass of MgSO₄ = 120.367 g/mol
Mass = 0.0338 mol × 120.367 g/mol = 4.068 g
Step 3: Mass of H₂O
Molar mass of H₂O = 18.015 g/mol
Moles of H₂O = 7 × 0.0338 mol = 0.2366 mol
Mass = 0.2366 mol × 18.015 g/mol = 4.262 g
✅ Final Theoretical Yields:
– Mass of anhydrous MgSO₄ = 4.068 g
– Mass of water vapor = 4.262 g
– Mass of anhydrous MgSO₄ = 4.068 g
– Mass of water vapor = 4.262 g