For the reaction A(g) 2B(g), the backwardreaction rate constant is higher than the forwardreaction rate constant by a factor of 2500, at 1000 K.[Given: R= 0.0831 L atm mol–1 K–1]KP for the reaction at 1000 K is

Answer

Equilibrium Constants Explanation

For the elementary reversible reaction A ⇌ 2B, the equilibrium constant in concentration units is the ratio of rate constants:

Kc = kf / kb = 1 / 2500 = 4.0 × 10−4

Because Δng = (2 − 1) = 1, we apply:

Kp = Kc(RT)Δng

At 1000 K:

RT = 0.0831 × 1000 = 83.1

Kp = 4.0 × 10−4 × 83.1 ≈ 0.033

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