Scrieti produsii de reactie rezultati din urmatoarele reactii de reducere:R-→O→II→1.NaBH4R’C-OOR’→?2.H3O 1.LiAlH45Seminar RCOFSAn
Answer
Reduction Products of Carbonyl and Carboxylic Acid Derivatives
NaBH₄ / H₃O⁺ reduces an aldehyde:
R–CHO → R–CH2OH
Product: Primary alcohol
NaBH₄ / H₃O⁺ reduces a ketone:
R–CO–R’ → R–CH(OH)–R’
Product: Secondary alcohol
LiAlH₄ / H₃O⁺ reduces an ester:
R–COOR’ → R–CH2OH + R’OH
Product: Two alcohols – one from acyl group and one from alkoxy group
LiAlH₄ / H₃O⁺ reduces a carboxylic acid:
R–COOH → R–CH2OH
Product: Primary alcohol
LiAlH₄ / H₃O⁺ reduces an acid chloride:
R–COCl → R–CH2OH
Product: Primary alcohol
LiAlH₄ / H₂O reduces a primary amide:
R–CONH₂ → R–CH2NH2
Product: Primary amine
LiAlH₄ / H₂O reduces a secondary amide:
R–CONHR’ → R–CH2–NHR’
Product: Secondary amine
LiAlH₄ / H₂O reduces a tertiary amide:
R–CONR’R” → R–CH2–NR’R”
Product: Tertiary amine