
Answer
Ligand Field Effects on Ni2+ (d8) Complexes and Their Magnetism
Cl− and H2O are weak-field ligands.
As a result, when Ni2+ (d8) forms complexes with them, it remains in a high-spin state.
Examples:
- [NiCl4]2− — tetrahedral
- [Ni(H2O)6]2+ — octahedral
Each of these retains two Unpaired Electron, so they are paramagnetic.
CO and PPh3 are strong-field ligands.
In Ni(CO)4 and Ni(PPh3)4, nickel is in the zero oxidation state (Ni(0)) with a d10 configuration.
These are diamagnetic due to full electron pairing.
CN− is also a strong-field ligand.
In the complex [Ni(CN)4]2−, Ni2+ (d8) adopts a square planar geometry due to pairing of electrons.
This results in a low-spin configuration, making it diamagnetic.
Conclusion:
Only Complexes A and D are paramagnetic with unpaired electrons.
All others are diamagnetic due to full pairing from strong-field ligands.
“Paramagnetic vs Diamagnetic” Fully explained
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