What set of reagents ( A and B ) would you use to effect the transformation below?

Answer

Phenylacetylene to trans-Styrene Transformation

🧪 Conversion of Phenylacetylene to trans-Styrene

Reaction Overview

C₆H₅–C≡CH → C₆H₅–CH=CH (trans)

🔬 Strategy

The conversion is achieved in two sequential steps:

  • Step A: Partial hydrogenation of the alkyne to form the cis-alkene
  • Step B: Isomerization of the cis-alkene to trans-alkene

Step A: Partial Hydrogenation to cis-Alkene

Reagents: H₂ / Lindlar’s Catalyst

Lindlar’s catalyst allows syn-addition of hydrogen across the alkyne to stop at the cis-alkene stage.

C₆H₅–C≡CH → C₆H₅–CH=CH (cis)

Step B: Isomerization to trans-Alkene

Reagents: Na / NH₃ (liquid ammonia)

A dissolving metal reduction converts the cis-alkene to the trans-isomer through a radical anion intermediate.

C₆H₅–CH=CH (cis) → C₆H₅–CH=CH (trans)

✅ Reagents Summary

Step Transformation Reagents Used
A Alkyne → cis-Alkene H₂ / Lindlar’s Catalyst
B cis-Alkene → trans-Alkene Na / NH₃ (liq.)

🧠 Summary

  • Use Hâ‚‚ with Lindlar’s catalyst for selective syn-addition to form the cis-alkene.
  • Follow with sodium in liquid ammonia to convert the cis-alkene to a stable trans-alkene.
  • This sequence provides high stereoselectivity for the trans-styrene product.

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