Draw the mechanism for this transformation:Note for advanced students: don’t worry if the product shown above might continue to react unde

Answer

Claisen Condensation Mechanism | Step-by-Step Organic Chemistry

🧪 Claisen Condensation Reaction – Full Mechanism Explained

🔹 Step 1: Introduction

This transformation is a classic Claisen condensation, which is a C–C bond-forming reaction between two esters or an ester and a ketone. A strong base, such as sodium ethoxide (NaOEt), is used to abstract an α-proton and generate an enolate ion.

Final Product: β-Keto Ester
Type: Mixed Claisen Condensation (Ketone + Ester)

🔬 Step-by-Step Reaction Mechanism

Step 1 – Enolate Formation:
Sodium ethoxide abstracts an α-hydrogen from the ketone, forming a resonance-stabilized enolate ion.
Step 2 – Nucleophilic Attack:
The enolate ion attacks the carbonyl carbon of the ester, producing a tetrahedral intermediate.
Step 3 – Elimination of Ethoxide:
The intermediate collapses, eliminating ethoxide and forming a new C=O bond.
Step 4 – Reprotonation (Optional):
The β-keto ester may be reprotonated under neutral or acidic conditions to stabilize the product.

📘 Summary Table

Step Description
Enolate Formation Base deprotonates α-carbon of ketone
Nucleophilic Attack Enolate attacks ester carbonyl carbon
Elimination Loss of ethoxide and reformation of carbonyl group
Protonation Formation of stable β-keto ester

✅ Final Product & Confirmation

The final product is a β-keto ester, formed via a condensation reaction between a ketone-derived enolate and an ester. This validates the reaction as a mixed Claisen condensation.

🧠 Conclusion

Claisen condensation is one of the most important carbon–carbon bond-forming reactions in organic chemistry. It is crucial for constructing β-keto esters, which are useful intermediates in complex molecule synthesis, including pharmaceuticals and natural products.

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